750 mL of nitrogen are collected over water at `25^@C` and 740 mm pressure. If the aqueous tension at this temperature is 23.8 mm Hg, calculate the mass of the dry gas.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the pressure of the dry nitrogen gas
The total pressure of the gas collected over water is given as 740 mm Hg, and the aqueous tension (the vapor pressure of water at 25°C) is 23.8 mm Hg. The pressure of the dry nitrogen gas can be calculated using the formula:

\[ P_{\text{gas}} = P_{\text{total}} - P_{\text{water}} \]
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