When 1 mole of ethanol Is mixed with 1 m...

When 1 mole of ethanol Is mixed with 1 mole of acetic acid, 0.67 mole of ethyl acetate is produced at equilibrium. Calculate `K_c` for the reaction.

0.25

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Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as: CH_(3)COOH(l)+C_(2)H_(5)OH(l)hArr CH_(3)COOC_(2)H_(5)(l)+H_(2)O(l) (1) Write the concentration ration (reaction, quotient), Q_(c) , for this reaction (note: Water is not in excess and is not a solvent in this reaction). (2) At 293K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. calculate the equilibrium constant. (3) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293K, 0.214 mol of ethyl acetate is found after sometime. has equilibrium been reached?

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