If position of a particle at time t is `(t^2 , 2t)` then calculate its velocity.

If the acceleration of a particle at time t seconds be 1.2t^(2)ft//s^(2) and velocity of the particle at time 2 seconds be 2.2 ft/s, then find its velocity at time 5 seconds.

The position x of a particle varies with t as x = at^(2)-bt^(3) . Calculate the acceleration after 2 seconds.

If position of a particle at instant t is given by x = t^(4) find acceleration of the particle.

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm//s^(2) , at time t seconds. If the velocity of the particel at time 2 seconds be 10cm/s, find its velocity at time t seconds.

The position time relation of a moving particle is x = 2t - 3t^2 What is the maximum (+) ve velocity of the particle?

The position-time relation of a moving, particle is x = 2t - 3t^2 :- When does the velocity of the particle become zero? (x is in metre and t is in second)

Position vector of a particle is related to time t as vecr=(t^2-1)hati+2thatj . The locus of the particle on the x-y plane is