The number of geometrical isomers for `[Pt(NH_(3))_(2)CI_(2)]` is

Options

A. 3
B. 4
C. 1
D. 2

Explanation

To determine the number of geometrical isomers for the coordination compound \([Pt(NH_3)_2Cl_2]\), we can follow these steps:

### Step 1: Identify the Coordination Number and Geometry
The coordination number of platinum in this complex is 4, as it is bonded to two ammonia (\(NH_3\)) ligands and two chloride (\(Cl\)) ligands. The geometry of a coordination compound with a coordination number of 4 can be either tetrahedral or square planar. For platinum(II) complexes, the geometry is typically square planar.

**Hint:** Remember that the geometry of a coordination complex can influence the types of isomers that can form.

### Step 2: Determine Possible Isomers
In square planar complexes, geometrical isomers arise from the arrangement of the ligands around the central metal atom. The two types of geometrical isomers are:
- **Cis Isomer:** The similar ligands are adjacent to each other.
- **Trans Isomer:** The similar ligands are opposite each other.

For \([Pt(NH_3)_2Cl_2]\):
- **Cis Isomer:** Both \(Cl\) ligands are adjacent to each other, and both \(NH_3\) ligands are adjacent to each other.
- **Trans Isomer:** One \(Cl\) ligand is opposite the other \(Cl\) ligand, and one \(NH_3\) ligand is opposite the other \(NH_3\) ligand.

**Hint:** Visualizing the arrangement of ligands can help you identify the types of isomers.

### Step 3: Count the Geometrical Isomers
From the arrangements discussed:
- We have identified one cis isomer and one trans isomer.

Thus, the total number of geometrical isomers for \([Pt(NH_3)_2Cl_2]\) is **2** (one cis and one trans).

**Hint:** When counting isomers, ensure that you consider all possible arrangements of the ligands.

### Conclusion
The number of geometrical isomers for the compound \([Pt(NH_3)_2Cl_2]\) is **2**.

**Final Answer:** 2