The conjugate acid of `overset(Theta)NH_(2)` is

Options

A. `N_(2)H_(4)`
B. `NH_(4)^(+)`
C. `NH_(2)OH`
D. `NH_(3)`

Explanation

To find the conjugate acid of \( \overset{\Theta}{NH_2} \) (which is the amide ion), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Conjugate Acid-Base Pairs**:
- According to the Brønsted-Lowry theory, an acid is defined as a proton (H\(^+\)) donor, while a base is a proton acceptor. The conjugate acid of a base is formed when the base accepts a proton.

2. **Identify the Given Species**:
- The species we have is \( \overset{\Theta}{NH_2} \), which is the amide ion.

3. **Add a Proton to the Given Species**:
- To find the conjugate acid, we need to add a proton (H\(^+\)) to the amide ion:
\[ \overset{\Theta}{NH_2} + H^+ \rightarrow NH_3 \]

4. **Determine the Resulting Species**:
- After adding the proton, we get \( NH_3 \), which is ammonia.

5. **Conclude the Result**:
- Therefore, the conjugate acid of \( \overset{\Theta}{NH_2} \) is \( NH_3 \).

### Final Answer:
The conjugate acid of \( \overset{\Theta}{NH_2} \) is \( NH_3 \).

---