In the following reaction
`H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH=CH_(2) overset(H_(2)O //H^(o+))(rarr) underset(("Major"),("product"))(A)underset(("Minor"),("product"))(B)`
The major product is

Options

A. `H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-underset(OH" ")underset(|" ")(CH)-CH_(3)`
B. `H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-underset(OH" ")underset(|" ")(CH_(2))`
C. `H_(3)C-underset(OH)underset(|)overset(CH_(3))overset(|)C- underset(CH_(3)" ")underset(|" ")(CH)-CH_(3)`
D. `underset(OH)underset(|)(CH_(2))-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-CH_(3)`

Explanation

To determine the major product of the given reaction, we need to analyze the reaction mechanism step by step.

### Step-by-Step Solution:

1. **Identify the Reactant**:
The reactant is an alkene, specifically 2-methyl-2-pentene (H₃C-CH(CH₃)-C=CH₂).

**Hint**: Recognize the structure of the alkene and the presence of the double bond.

2. **Protonation of the Alkene**:
The alkene reacts with H⁺ (from H₂O/H⁺), leading to the protonation of the double bond. This creates a carbocation intermediate. There are two possible carbocation formations: a secondary carbocation and a tertiary carbocation.

**Hint**: Remember that the more substituted the carbocation, the more stable it is.

3. **Formation of Carbocation**:
- If the double bond does not rearrange, a secondary carbocation is formed.
- If the double bond rearranges via a methyl shift, a tertiary carbocation is formed, which is more stable.

**Hint**: Consider the stability of carbocations; tertiary > secondary > primary.

4. **Nucleophilic Attack**:
Water (acting as a nucleophile) will attack the carbocation. In the case of the secondary carbocation, water will attack to form a secondary alcohol. In the case of the tertiary carbocation, water will attack to form a tertiary alcohol.

**Hint**: A nucleophile attacks the positively charged carbon to form an alcohol.

5. **Deprotonation**:
After the nucleophilic attack, a proton (H⁺) is removed from the oxygen of the alcohol, leading to the formation of the final alcohol product.

**Hint**: Look for the loss of a proton to stabilize the alcohol.

6. **Identify Major and Minor Products**:
The major product will be the one derived from the more stable tertiary carbocation, while the minor product will be from the less stable secondary carbocation.

**Hint**: Compare the stability of the products to determine which is major and which is minor.

### Conclusion:
The major product (A) is the tertiary alcohol formed from the rearrangement of the carbocation, while the minor product (B) is the secondary alcohol. Therefore, the major product is the one derived from the tertiary carbocation.

### Final Answer:
The major product is **C (tertiary alcohol)**.

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