The escape speed from earth's surface is `11kms^(-1)`. A certain planet has a radius twice that of earth but its mean density is the same as that of the earth. Find the value of the escape speed from the planet.
Text Solution
AI Generated Solution
To find the escape speed from a planet that has a radius twice that of Earth but the same mean density as Earth, we can follow these steps:
### Step 1: Understand the escape speed formula
The escape speed \( v \) from the surface of a celestial body is given by the formula:
\[
v = \sqrt{\frac{2GM}{R}}
\]
where \( G \) is the universal gravitational constant, \( M \) is the mass of the body, and \( R \) is its radius.
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