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Poistive and negative point charges of e...

Poistive and negative point charges of equal magnitude are kept at `(0, 0, a/2)` and `(0, 0, (-a)/(2))` respectively. The work done by the electric field when another poistive point charge is moved from `(-a, 0, 0)` to `(0, a, 0)` is

A

positive

B

negative

C

zero

D

depends on the path connecting the initial and final positions

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the work done by the electric field when a positive point charge is moved from the point \((-a, 0, 0)\) to the point \((0, a, 0)\) in the presence of a positive charge at \((0, 0, a/2)\) and a negative charge at \((0, 0, -a/2)\). ### Step-by-Step Solution: 1. **Identify the Charges and Their Positions**: - We have a positive charge \(+q\) at the position \((0, 0, a/2)\). - We have a negative charge \(-q\) at the position \((0, 0, -a/2)\). - We want to move a positive test charge \(+Q\) from the point \((-a, 0, 0)\) to the point \((0, a, 0)\). ...
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