Which of the following is the electronic configuration of an atom in its first excited state if that atom is isoelectronic with `O_(2)` ?

Options

A. `[Ne]3s^(2)3p^(4)`
B. `[Ne]3s^(2)3p^(3)3d^(1)`
C. `[Ne]3s^(1)3p^(3)`
D. None of these

Explanation

To determine the electronic configuration of an atom in its first excited state that is isoelectronic with O₂, we can follow these steps:

### Step 1: Determine the number of electrons in O₂
Oxygen (O) has an atomic number of 8, which means each oxygen atom has 8 electrons. Since O₂ consists of two oxygen atoms, the total number of electrons in O₂ is:
\[ \text{Number of electrons in O₂} = 2 \times 8 = 16 \]

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