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0.45 gm of an organic compound gave on c...

0.45 gm of an organic compound gave on combution 0.792 gm of `CO_2` and `0.324gm` of water. 0.24 gm of the same substance was Kjeldahlised and the ammonia liberated was absorbed in 50.0 ml of `(M)/(8H_2SO_4)`. The excess acid required 77.0 ml of `(N)/(10)NaOH` for complete neutralisation. Calculate the empirical formula of the compound.

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To find the empirical formula of the organic compound, we will follow these steps: ### Step 1: Calculate the percentage of Carbon in the organic compound Given that 0.792 g of CO₂ is produced from the combustion of 0.45 g of the organic compound: 1. The molar mass of CO₂ = 44 g/mol (12 g/mol for C + 32 g/mol for O). 2. The mass of Carbon in CO₂ can be calculated as: \[ ...
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