(i) If a, b, c, are in A.P. then show that `ax….+….by +c=0` passes through a fixed point. Find then fixed point.
(ii) If `9a^(2)+16b^(2)-24ab-25c^(2)=0,` then the family of straight lines `ax+by+0` is concurrent at the point whose co-ordinates are given by `"________"`
(iii) If `3a+4b-5c=0,` then the family of straight lines `ax+by+c=0` passes through a fixed point. Find the coordinates of the point.

Explanation

Let's solve the question step by step.

### Part (i)
**Given:** If \( a, b, c \) are in A.P., show that the line \( ax + by + c = 0 \) passes through a fixed point.

1. **Understanding A.P.:** Since \( a, b, c \) are in A.P., we have:
\[
2b = a + c \quad \Rightarrow \quad a + c - 2b = 0
...