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The conductivity of a saturated solution...

The conductivity of a saturated solution of `Ag_(3)PO_(4)` is `9 xx 10^(-6) S m^(-1)` and its equivalent conductivity is `1.50 xx 10^(-4) Sm^(2) "equivalent"^(-1)`. Th `K_(sp)` of `Ag_(3)PO_(4)` is:-

A

`4xx10^(-12)`

B

`2.5xx10^(-13)`

C

`25xx10^(-9)`

D

`10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
D
`1.53=(1000xx3.06xx10^(-6))/("normality")`
normality `=2xx10^(-3)M`
molarity `=(2xx10^(-3))/(2)=10^(-3)M`
`K_(SP)=10^(-6)M`
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