Three isometic compounds M,N and P `(C_(5)H_(10)O)` give the following tests
(i) M and P react with sodium bisulfite to form an adduct J
(ii) N Comsumes I mol of bromine and also gives turbidity with conc. HCl/anhydrous `ZnCl_(2)` after prolong heating
(iii) M reacts with excess of iodine in alkaline solution to give yellow crystalline compound with a characterstics smell.
(iv) p-Rosaniline treated with sulphur dioxide develops pink colour on shaking with P the structure of M,N and P, respectively are

Options

A.
B.
C.
D.

Answer

To solve the problem, we need to analyze the information given about the three isomeric compounds M, N, and P (C5H10O) based on the tests they undergo.

### Step-by-Step Solution:

1. **Identifying Compound M:**
- **Test:** M and P react with sodium bisulfite to form an adduct J.
- **Conclusion:** This indicates that both M and P contain a carbonyl group (aldehyde or ketone).

2. **Identifying Compound N:**
- **Test:** N consumes 1 mol of bromine and gives turbidity with concentrated HCl/anhydrous ZnCl2 after prolonged heating.
- **Conclusion:** The consumption of bromine suggests that N has a double bond (alkene) or an alcohol group. The turbidity with ZnCl2 indicates that N is likely an alcohol, specifically a secondary or tertiary alcohol, which can react with ZnCl2 to form an alkyl halide.

3. **Identifying Compound M (continued):**
- **Test:** M reacts with excess iodine in alkaline solution to give a yellow crystalline compound with a characteristic smell.
- **Conclusion:** This indicates that M is a methyl ketone, which can undergo the iodoform reaction to form a yellow precipitate (iodoform).

4. **Identifying Compound P:**
- **Test:** P-rosaniline treated with sulfur dioxide develops a pink color on shaking with P.
- **Conclusion:** This reaction is characteristic of aldehydes, indicating that P is likely an aldehyde.

### Structures of Compounds M, N, and P:
- **Compound M:** Methyl ketone, likely 3-pentanone (CH3COCH2CH2CH3).
- **Compound N:** A secondary or tertiary alcohol, likely 2-pentanol (CH3CH(OH)CH2CH2CH3).
- **Compound P:** An aldehyde, likely pentanal (CH3(CH2)3CHO).

### Final Structures:
- **M (3-pentanone):** CH3COCH2CH2CH3
- **N (2-pentanol):** CH3CH(OH)CH2CH2CH3
- **P (pentanal):** CH3(CH2)3CHO

### Summary:
- The structures of M, N, and P are:
- M: 3-Pentanone
- N: 2-Pentanol
- P: Pentanal