The maximum valume (in cu.m) of the right circluar cone having slant height 3 m is

Answer

2

Explanation

`R^(2)+H^(2)=9impliesR^(2)=9-H^(2)`
volume `=1/3pi H(9-H^(2))`
`(H^(2)+(9-H^(2))/2+(9-H^(2))/2)/3 geroot(3)(H^(2)((9-H^(2))/2)^(2))`
i.e. `[H(9-H^(2))]^(2//3)le3xx4^(1//3)`
Hence volume `le1/3xxpixx3sqrt(3)xx2le2pisqrt(3)`