When a jar containing gaseous mixture of equal volumes of `CO_(2)` and `H_(2)` is placed in a solution of sodium hydroxide, the solution level will

Options

A. Rise
B. Fall
C. Remain constant
D. Become zero

Answer

To solve the question regarding the behavior of a gaseous mixture of equal volumes of CO₂ and H₂ when placed in a sodium hydroxide (NaOH) solution, we can follow these steps:

### Step 1: Understand the Components
We have a mixture of gases: carbon dioxide (CO₂) and hydrogen (H₂). The jar containing this mixture is placed in a solution of sodium hydroxide (NaOH).

### Step 2: Analyze the Reaction
When CO₂ is introduced to an NaOH solution, it reacts with the sodium hydroxide to form sodium carbonate (Na₂CO₃) or sodium bicarbonate (NaHCO₃) depending on the concentration of NaOH and the amount of CO₂. The reaction can be represented as:
\[ \text{CO}_2 (g) + 2 \text{NaOH} (aq) \rightarrow \text{Na}_2\text{CO}_3 (aq) + \text{H}_2 (g) \]
or
\[ \text{CO}_2 (g) + \text{NaOH} (aq) + \text{H}_2\text{O} (l) \rightarrow \text{NaHCO}_3 (aq) \]

### Step 3: Consider the Behavior of H₂
Hydrogen (H₂) is an inert gas in this context and does not react with sodium hydroxide. Therefore, it will remain in the gaseous state and will not contribute to any change in the solution level.

### Step 4: Determine the Effect on Solution Level
As CO₂ reacts with NaOH, it gets consumed, leading to a decrease in the volume of gas in the jar. Since the gas volume decreases, the pressure inside the jar will also decrease, which can cause the liquid level in the NaOH solution to rise slightly due to the reduction in gas pressure above the liquid.

### Conclusion
The solution level will rise due to the reaction of CO₂ with NaOH, despite the negligible increase in the overall volume of the solution.

### Final Answer
The solution level will rise.

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