Two bodies of masses 4 kg and 9 kg are separated by distance of 60 cm. A 1 kg mass is placed in between these two masses. If the net force on 1 kg is zero, then its distance from 4 kg mass is

Options

A. 26 cm
B. 30 cm
C. 28 cm
D. 24 cm

Answer

D

Explanation

Given, `m_1 = 4 kg , m_2 = 9 kg and r = 60 cm` and addition mass `= 1kg`
Let the distance of mass from mass `m_1` is `x`.
`therefore x = (r)/( sqrt((m_2)/(m_1) ) + 1 ) = (60 )/( sqrt((9)/(v) + 1) )= (60)/((3)/(2) +1) = 24 cm`