Home
Class 10
MATHS
Prove that the parallelogram circumscrib...

Prove that the parallelogram circumscribing a circle is a rhombus.

Text Solution

Verified by Experts

The correct Answer is:
48cm
Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER-2

    KUMAR PRAKASHAN|Exercise Section C|14 Videos
  • QUESTION PAPER-2

    KUMAR PRAKASHAN|Exercise Section -A- True & False|3 Videos
  • QUESTION PAPER -1

    KUMAR PRAKASHAN|Exercise SECTION D ( Answer the following as required with calculations) |1 Videos
  • REAL NUMBERS

    KUMAR PRAKASHAN|Exercise TEST YOUR SKILLS|26 Videos

Similar Questions

Explore conceptually related problems

Prove that a cyclic parallelogram is a rectangle.

Area of a parallelogram =_____

State whether each of the following statements is true or false : The perimeter of a square circumscribing a circle of radius a cm is 8a cm.

If one of the vertices of the square circumscribing the circle |z - 1| = sqrt2 is 2+ sqrt3 iota . Find the other vertices of square

Using vectors, prove that the parallelogram on the same base and between the same parallels are equal in area.

Prove that the area of the circle with radius r is pi r^2

Perpendiculars are drawn from the angles A, B and C of an acute-angled triangle onthe opposite sides, and produced to meet the circumscribing circle. If these produced parts are alpha., beta, gamma, respectively, then show that, then show that a/alpha+b/beta+c/gamma=2(tanA+tanB+tanC).

The equation of the circle circumscribing the triangle whose sides are the lines y = x + 2, 3y = 4x and 2y = 3x is ……