Home
Class 12
CHEMISTRY
phenol associates in benzene to a certai...

phenol associates in benzene to a certain extent in dimerisation reaction. A solution containing 0.02 kg of phenol in 1.0 kg of benzene has its freezing point depressed 0.69 k. [`K_(f)(C_(6)H_(6)) =5.12 k kg"mol"^(-1)`]. The degree of association:

A

73.3

B

50.1

C

42.3

D

25.1

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The amount of benzene that wil separate out (in grams) if a solution containing 7.32 g of triphenylmethane in 1000g of benzene is cooled to a temperature which is 0.2^(@)C below the freezing point of benzene? (K_(f)=5.12K-Kg//"mol")

Calculatate the mass of compound (molar mass = 256 g mol^(-1) be the dissolved in 75 g of benzene to lower its freezing point by 0 .48 k(k_(f) = 5. 12 k kg mol ^(-1) .

Calculate the amount of KCl which must be added to 1kg of water so that the freezing point is depressed by 2K . ( K_(f) for water =1.86K kg "mol"^(-1) ).

The freezing point of a solution contaning 0.3 g of acetic acid in 43 g of benzene reduces by 0.3^(@) . Calculate the Van's Hoff factor "( K_(f) for benzene = 5.12 K kg mol^(-1) )"

The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

1.00 g of a non-electrolyte solute (molar mass 250g mol^(–1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant K_(f) of benzene is 5.12 K kg mol^(–1) , the freezing point of benzene will be lowered by:-

1.00 g of a non-electrolyte solute (molar mass 250g mol^(–1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant K_(f) of benzene is 5.12 K kg mol^(–1) , the freezing point of benzene will be lowered by:-

A certain aqueous solution boils at 100.303^@C . What is its freezing point ? K_b for water = 0.5 "mol"^(-1) and K_f = 1.87 K "mol"^(-1)

1.0 g of non-electrolyte solute dissolved in 50.0 g of benzene lowered the freezing point of benzene by 0.40 K . The freezing point depression constant of benzene is 5.12 kg mol^(-1) . Find the molecular mass of the solute.