KMnO4 can be prepared fromK2MnO4 as per ...

`KMnO_4` can be prepared from`K_2MnO_4` as per the reaction:
`3MnO_4^(2-) + 2H_2O ⇋ 2MnO_4^(-) + MnO_2+ 4OH^(-)`
The reaction can go the completion by removing `OH^(ɵ)` ions by adding.

A

KOH

B

`CO_2`

C

`SO_2`

D

HCl

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The correct Answer is:

B

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