In the given reaction `CH_3MgBr+D_2Orarr(X),` (X) will be

Options

A. `CH_4`
B. `CH_3D`
C. `CH_2D_2`
D. `CH_3OH`

Answer

To solve the reaction `CH3MgBr + D2O → (X)`, we can break down the process step by step:

### Step 1: Identify the Reactants
We have two reactants:
- **CH3MgBr** (Methylmagnesium bromide), which is a Grignard reagent.
- **D2O** (Deuterated water), where D represents deuterium, an isotope of hydrogen.

### Step 2: Understand the Reaction Mechanism
Grignard reagents like CH3MgBr are strong nucleophiles. They react with electrophiles, and in this case, D2O acts as the electrophile.

### Step 3: Nucleophilic Attack
The methyl group (CH3-) from CH3MgBr will attack the deuterium in D2O. The reaction can be visualized as follows:
- The nucleophilic methyl group (CH3-) attacks the deuterium (D) in D2O.

### Step 4: Formation of the Product
When CH3- attacks D2O, it will replace one of the deuterium atoms, forming:
- **CH3D** (Methyl deuteride), where one hydrogen in the methyl group has been replaced by deuterium.

### Step 5: Byproducts
The byproduct of this reaction will be:
- **Mg(Br)(OD)**, which is a magnesium salt formed from the remaining parts of the reactants.

### Conclusion
Thus, the product (X) formed from the reaction `CH3MgBr + D2O` is **CH3D**.

### Final Answer
(X) = **CH3D**

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