`(p^^~q)` is logically equal to
1. `p -> q`
2. `~ p->q`
3. `p -> ~ q`
4. `~(p ->q)`

p to q is logically equivalent to

(p ^^ ~ q)vv q is logical equivalent to (a) p vv q (b) ~P (c) p (d) ~q

The logical statement (p to q) vv (q to ~ p) is :

The incorrect statement is (A) p →q is logically equivalent to ~p ∨ q. (B) If the truth-values of p, q r are T, F, T respectively, then the truth value of (p ∨ q) ∧ (q ∨ r) is T. (C) ~(p ∨ q ∨ r) = ~p ∧ ~q ∧ ~r (D) The truth-value of p ~ (p ∧ q) is always T

(p^^~q)^^(~p^^q) is

(p^^~q)^^(~p^^q) is

(p ^^ ~q) ^^ (~p vv q) is

If p= q + 2 then p gt q .

The logically equivalent proposition of phArrq is (p^^q)vv(p^^q) b. (p=>q)^^(p=>q) c. (p^^q)vv(p=>q) d. (p^^q)(pvvq)

The Boolean Expression (p^^~ q)vvqvv(~ p^^q) is equivalent to : (1) ~ p^^q (2) p^^q (3) pvvq (4) pvv~ q