Evaluate `intdx/(x[10+7log_ex+(log_ex)^2])`

Evaluate: intdx/(x(1+log_ex)^2)

Evaluate: int(e^(5(log)_e x)-e^(4(log)_ex))/(e^(3(log)_e x)-e^(2logx))dx

Evaluate int_1^e cos(log_ex)/xdx

Evaluate : int [ log (log x) +(1)/((log x)^(2)) ] dx

Evaluate: intdx/(sqrt (1+x^2)sqrt (log(x+sqrt (1+x^2))))

inte^(log_ex)cosxdx

I=int \ log_e (log_ex)/(x(log_e x))dx

If log_(y)x +log_(x)y = 7 , then the value of (log_(y)x)^(2) +(log_(x)y)^(2) , is

int1/(xcos^2(log_ex))dx

The integral inte^x(f(x)+f\'(x))dx can be solved by using integration by parts such that: I=inte^xf(x)dx+inte^xf\'(x)dx=e^xf(x)-inte^xf\'(x)dx+inte^xf\'(x)dx=e^xf(x)+C , and inte^(ax)(f(x)+(f\'(x))/a)dx=e^(ax)f(x)/a+C ,Now answer the question: int{log_e(log_ex)+1/(log_ex)^2}dx is equal to (A) log_e(log_ex)+C (B) xlog_e(log_ex)-x/log_ex+C (C) x/log_ex-log_ex+C (D) log_e(log_ex)-x/log_ex+C