Let `S=4/19+44/19^2+444/19^3+….+" up to " oo` . Then S is equal to

Let S= 4/19+44/(19)^2+444/(19)^3+...oo then find the value of S

Let S_(k) = (1+2+3+...+k)/(k) . If S_(1)^(2) + s_(2)^(2) +...+S_(10)^(2) = (5)/(12)A , then A is equal to

If 8x^(3) - 14x^(2) - 19x - 8 is divided by 4x+ 3 then find the quotient and the remainder.

One ticket is selected at random from 100 tickets numbered 00,01,02,...,98,99. Suppose S and T are the sum and product of the digits of the number on the ticket, then the probability of getting S=9 and T=0 is 2//19 b. 19//100 c. 1//50 d. none of these

Let S denote sum of the series 3/(2^3)+4/(2^4 .3)+5/(2^6 .3)+6/(2^7 .5)+oo Then the value of S^(-1) is __________.

Find the number of terms in the series 20 ,19 1/3,18 2/3... the sum of which is 300. Explain the answer.

The 29^(th) term of an A.P is twice its 19^(th) term. Its 9^(th) term is equal to

Let S_n = cos ((n pi )/( 10)) , n = 1,2,3,…… then the value of ( s_1 s_2 ……s_(10))/( s_1 + s_2 +…….. +s_(10)) is equal to

Identify the nature of hydrides that are formed by the elements of atomic numbers 15, 19, 23, 44 with dihydrogen. Compare their reactivity towards water.