[(^n C0+^n C3+)1//2(^n C1+^n C2+^n C4+^n...

`[(^n C_0+^n C_3+)1//2(^n C_1+^n C_2+^n C_4+^n C_5]^2+3//4(^n C_1-^n C_2+^n C_4-^n C_5+)^2=` `3` b. `4` c. `2` d. `1`

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The correct Answer is:

`(1+omega)^(n) = .^(n)C_(0) + .^(n)C_(1) +omega+"....."`
`= (.^(n)C_(0)+.^(n)C_(3) +"....")+(.^(n)C_(1)+.^(n)C_(4)+".....")((-1+sqrt(3)i)/(2))+(.^(n)C_(2)+.^(n)C_(5)+"....")((-1-sqrt(3)t)/(2))`
`= (.^(n)C_(0) + .^(n)C_(3) + "....") -1/2 (.^(n)C_(1) + .^(n)C_(2) + .^(n)C_(4) + .^(n)C_(5)".....")+(isqrt(3))/(2)(.^(n)C_(1)-.^(n)C_(2)+.^(n)C_(4)-.^(n)C_(5) + "....")`
Equating the modulus, we get `|(-omega^(2))^(n)| = 1`.

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