A body slides over an inclined plane of forming an angle of `45^(@)` with the horizontal. The distance x travelled by the body in time t is described by the equation `x=kt^(2)` where `k=1.732`. The coefficinet of friction between the body and the plane has a value .

A body slides down on an inclined plane of inclination 37^(@) with horizontal. The distance travelled by the body in time t is given by s = t^(2) . Find the friction coefficient between the body and the incline.

A body is sliding down an inclined plane forming an angle 30^(@) with the horizantal. If the coefficient of friction is 0.3 then acceleration of the body is

A block is at rest on an inclined plane making an angle alpha with the horizontal . As the angle alpha of the incline is increased the block starts slipping when the angle of inclination becomes theta . The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle theta to the horizontal. Then the coefficient of friction is equal to

A body of mass m slides down an inclined plane making an angle of 45^(@) with the horizontal. If the coefficient of friction between the body and the plane be 0.3, the acceleration of the body is approximately equal to :

A body of mass m is launched up on a rough inclined plane making an angle 45^(@) with horizontal If the time of descent between plane and body is

A brick of mass 2kg begins to slide down on a plane inclined at an angle of 45^(@) with the horizontal. The force of friction will be

When body slides down from rest along smooth inclined plane making angle of 45^(@) with the horizontal, it takes time T When the same body slides down from rest along a rough inclined plane making the same angle and through the same distance it is seen to take time pT , where p is some number greater that 1. Calculate late the coefficient of friction beween the body and the rough plane. .