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The velocity (V) of a particle (in cm/s)...

The velocity (V) of a particle (in cm/s) is given in terms of time (t) in sec by the equation `V=at+(b)/(c+t)`. The dimensions of a, b and c are

A

`L^2 , M , LT^(-2)`

B

`LT^2 , LT l L`

C

`LT^(-2) , L , T`

D

`L , LT , T^2`

Text Solution

Verified by Experts

The correct Answer is:
C
As C is added to t, therefore , C has the dimensions of T.
As `b/t = V, `
`b = V xx t = LT^(-1) xx T = (L)`
From `V = at, a = v/t = (LT^(-1))/(T) = [LT^(-2)]`
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