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Find the ratio of the distance moved by ...

Find the ratio of the distance moved by a free-falling body from rest in fourth and fifth seconds of its journey.

A

`4:5`

B

`7:9`

C

`16:25`

D

`1:1`

Text Solution

Verified by Experts

The correct Answer is:
B
Distance covered in nth second is given by
`s_(n)=u+(a)/(2)(2n-1)`
Given : `u=0`, a=g
`:.s_(4)=(g)/(2)(2xx4-1)=(7g)/(2)`
`s_(s)=(g)/(2)(2xx5-1)=(9g)/(2)`
`:.(s_(4))/(s_(5))=(7)/(9)`
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