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. If the velocity of a particle is `(10 + 2 t ^(2))` m/s , then the average acceleration of the particle between 2s and 5s is

A

`2"m/s"^(2)`

B

`4"m/s"^(2)`

C

`12"m/s"^(2)`

D

`14"m/s"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(V=10+2t^(2),V_(2)=10+2(2)^(2)=10+8=18):}`
`V_(1)=10+2(5)^(2)=60`
`ltagt = (V_(2)-V_(1))/(t_(2)-t_(1))=(60-18)/(3)=(42)/(3)=14"m/s"^(2)`
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