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A stone of mass 0.5 kg tied with a strin...

A stone of mass 0.5 kg tied with a string of length 1 metre is moving in a circular path with a speed of 4 m/sec. The tension acting on the string in Newton is-

A

2

B

8

C

0.2

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
B
`T =("mv"^(2))/(r)`
`= (0.5 xx (4)^(2))/(1)=8N`
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