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A uniform circular disc of radius 50 cm ...

A uniform circular disc of radius 50 cm at rest is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2 rad `s^(-1)`. Its net acceleration in `ms^(-2)` at the end of 2 s is approximately

A

`8.0`

B

`7.0`

C

`6.0`

D

`3.0`

Text Solution

Verified by Experts

The correct Answer is:
A
Particle at periphery will have both radial and tangential acceleration
`a_(p)=R alpha = 0.5 xx 2 = 1 " ms"^(-2)`
`omega = omega_(s)+alpha t`
`omega = 0 +2 xx 2 = 4 " rad/sec"`
`a_(s) = omega^(2) R=(4)^(2) xx 0.5 = 16 xx 0.5 = 8 " ms"^(-2)`
`a_(tital)= sqrt(a_(n)^(2)+ a_(t)^(2))= sqrt(I^(2)+ 8^(2))=8 " ms"^(-2)`
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