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The photoelectric threshold frequency of...

The photoelectric threshold frequency of a metal is v. When light of frequency 4v is incident on the metal . The maximum kinetic energy of the emitted photoelectrons is

A

4 hv

B

3 hv

C

5 hv

D

`(5 hv)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
The maximum kinetic energy of the emitted electron is given by.
`K_("max") = h v - phi_(n) = h(4v - v) = h (3v)`
`K_("max") = 3hv`
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