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What is the molality of a solution conta...

What is the molality of a solution containing 40 g of NaOH in 1000 mL of water ?

Text Solution

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Given, `w_(B) = 40`
Volume of water = 1000 mL
As we know, molality `= ("Number of moles of solute")/("Mass of solvent in kg")`
`((40)/(40))/(1 kg) = 1` molal
[`because` Density of water `= 1 g cm^(-1)` and `therefore` Mass = Density `xx` vol.]
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