Find out the limiting reagent when 5g of `H_2` reacts with 24g of `O_2` to form water.

Explanation

`{:(" Stoichiometric " :2H_(2)(g)+O_(2)(g) to 2H_(2)O(l)),(" Mass of rec tan ts ":" " 5g " "24g),(" Mass of rec tan ts ": " "2.5 " "0.75):}`
Ratio of moles (H : O) needed for complete reaction `=2 : 1" or "2.5 : 1.25`.
Since number of moles of `O_2` is less than required, `O_2` is the limiting reagent.