An open vessel contains air at `29^(@)C`. To what temperature it must be heated to expel one-third of the air?

Explanation

Let the volume of the vessel = 1L. Initial no. of moles = `n_1`. Find no. of moles,`n_(2)= (2"/"3)n_(1), T_(1)= 273+29= 302K`
Since P and V are constants, nRT= constant
`n_(1)T_(1)= n_(2)T_(2) implies n_(1) xx 302= (2"/"3)n xx T_(2) implies T_(2)= (302xx 3)"/"2= 453 K= 180^(@)C`.