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A stone is thrown vertically upwards. Wh...

A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is `10ms^(-1)`, then maximum height attained by the stone `(g=10ms^(-2))`

A

25m

B

10m

C

15m

D

20m

Text Solution

Verified by Experts

The correct Answer is:
B

`v^(2)=u^(2)-2g(h/2):." "(10)^(2)=u^(2)-gh" ":.u^(2)=(100+gh)`
Now `h=(u^(2))/(2g)=(100+gh)/(2g)`
`h=5+h/2` (as `2g=20m//s^(2)`)`" ":.h=10m`
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