A particle of mass `4m` which is at rest explodes into masses `m`, `m` and `2m`, two of the fragments of masses `m` and `2m` are found to move with equal speed `v` each in opposite directions. The total mechanical energy released in the process of explosion is

Options

A. `mv^(2)`
B. `2mv^(2)`
C. `1//2mv^(2)`
D. `4mv^(2)`

Answer

B

Explanation

`0 = 2mv - mv + mv rArr v = -v`
Total mechanical energy relased
`= (1)/(2) (m + m + 2m)v^(2) = 2mv^(2)`