The term which accounts for intermolecular force in van der Waal's equation is :

Options

A. `(V-b)`
B. `(RT)^(-1)`
C. `(P+a//V^(2))`
D. `RT`

Explanation

To solve the question regarding the term that accounts for intermolecular forces in van der Waals' equation, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Van der Waals Equation**:
The van der Waals equation is given by:
\[ \left( P + \frac{a n^2}{V^2} \right)(V - nb) = nRT \]
Here, \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the temperature.

2. **Identify the Terms**:
In the equation, there are two correction terms:
- The term \( \frac{a n^2}{V^2} \) accounts for the intermolecular forces of attraction.
- The term \( nb \) accounts for the volume occupied by the gas particles themselves.

3. **Focus on Intermolecular Forces**:
The term \( a \) in the equation represents the strength of the intermolecular forces. The larger the value of \( a \), the stronger the intermolecular forces between the gas molecules.

4. **Conclusion**:
Therefore, the term that accounts for intermolecular forces in van der Waals' equation is \( \frac{a n^2}{V^2} \).

### Final Answer:
The term which accounts for intermolecular force in van der Waals' equation is \( \frac{a n^2}{V^2} \).

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