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When a = (4)/(3), the value of 27 a ^(3)...

When `a = (4)/(3),` the value of `27 a ^(3)- 108 a ^(2) + 141 a - 31 ` is

A

A)261

B

B)`-253`

C

C)`-245`

D

D)`29`

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AI Generated Solution

The correct Answer is:
To find the value of the expression \( 27a^3 - 108a^2 + 141a - 31 \) when \( a = \frac{4}{3} \), we will substitute \( a \) into the expression and simplify step by step. ### Step 1: Substitute \( a \) into the expression We start with the expression: \[ 27a^3 - 108a^2 + 141a - 31 \] Substituting \( a = \frac{4}{3} \): \[ 27\left(\frac{4}{3}\right)^3 - 108\left(\frac{4}{3}\right)^2 + 141\left(\frac{4}{3}\right) - 31 \] ### Step 2: Calculate \( a^3 \) and \( a^2 \) First, we calculate \( a^3 \) and \( a^2 \): \[ a^3 = \left(\frac{4}{3}\right)^3 = \frac{4^3}{3^3} = \frac{64}{27} \] \[ a^2 = \left(\frac{4}{3}\right)^2 = \frac{4^2}{3^2} = \frac{16}{9} \] ### Step 3: Substitute \( a^3 \) and \( a^2 \) back into the expression Now substitute these values back: \[ 27\left(\frac{64}{27}\right) - 108\left(\frac{16}{9}\right) + 141\left(\frac{4}{3}\right) - 31 \] ### Step 4: Simplify each term 1. The first term: \[ 27 \cdot \frac{64}{27} = 64 \] 2. The second term: \[ 108 \cdot \frac{16}{9} = 12 \cdot 16 = 192 \] 3. The third term: \[ 141 \cdot \frac{4}{3} = \frac{564}{3} = 188 \] 4. The last term remains as is: \[ -31 \] ### Step 5: Combine all the terms Now we combine all the simplified terms: \[ 64 - 192 + 188 - 31 \] ### Step 6: Perform the arithmetic 1. Combine \( 64 - 192 \): \[ 64 - 192 = -128 \] 2. Add \( 188 \): \[ -128 + 188 = 60 \] 3. Subtract \( 31 \): \[ 60 - 31 = 29 \] ### Final Answer The value of the expression when \( a = \frac{4}{3} \) is: \[ \boxed{29} \]
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MOTHERS-ALGEBRA -MULTIPLE CHOICE QUESTION
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  17. If x^2+y^2+z^2=133,xy +yz + zx = 114 and xyz = 216, then the value of ...

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