Calculate the energy of a photon of light having frequency of 6 x 10^15 s-1

Explanation

Momentum = P= ?
Frequency = `v = 6 xx 10^14 Hz`
`P = (hv)/(c)`
`= (6.62 xx 10^(-34) xx 6 xx 10^14)/(3 xx 10^8)`
`= 13.24 xx 10^(-34 + 14 - 8)`
`= 13.24 xx 10^(-34 + 14 - 8)`
`= 13.24 xx 10^(-28)`
`P = 13.24 xx 10^(-28) `Kg m/s
or `P = 1.324 xx 10^(-27) kg m//s`