IUPAC name of the following compound is
`CH_(3)-CH=CH-CH_(2)-C-=CH`

Options

A. Hex-2-en-5-yne
B. Hex-5-yn-2-ene
C. Hex-4-en-1-yne
D. Hex-1-yn-4-ene

Answer

To determine the IUPAC name of the compound `CH₃-CH=CH-CH₂-C≡CH`, we can follow these steps:

### Step 1: Identify the longest carbon chain
First, we need to identify the longest continuous carbon chain in the compound. In this case, the longest chain consists of 6 carbon atoms.

### Step 2: Number the carbon chain
Next, we need to number the carbon chain. We will start numbering from the end that gives the lowest numbers to the multiple bonds (double and triple bonds).

- If we number from the left (starting from CH₃), we get:
1. CH₃
2. CH
3. CH
4. CH₂
5. C
6. C

This gives the double bond at position 3 and the triple bond at position 5.

- If we number from the right (starting from C≡CH), we get:
1. C
2. CH₂
3. CH
4. CH
5. CH₃

This gives the triple bond at position 1 and the double bond at position 4.

Since we prefer the numbering that gives the lowest locants to the multiple bonds, we will start from the right.

### Step 3: Identify the types of bonds
In this compound, we have:
- A double bond (alkene) at position 4.
- A triple bond (alkyne) at position 1.

### Step 4: Construct the name
According to IUPAC nomenclature:
- The base name is derived from the longest carbon chain, which has 6 carbons, so it is "hex".
- The presence of a triple bond (alkyne) takes precedence over the double bond (alkene) in naming, so we will indicate the triple bond first.
- The double bond will be indicated with the suffix "ene".

Thus, we will have:
- "hex" for the 6 carbon atoms.
- "1-yne" for the triple bond at position 1.
- "4-ene" for the double bond at position 4.

### Step 5: Combine the elements
Combining these, we get the final IUPAC name as:
**Hex-4-ene-1-yne**

### Final Answer
The IUPAC name of the compound `CH₃-CH=CH-CH₂-C≡CH` is **Hex-4-ene-1-yne**.

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