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Find the least numbers which should be added to 3857 so that the sum is exactly divisible by 5, 6, 4 and 3

A

43

B

3

C

33

D

17

Text Solution

AI Generated Solution

The correct Answer is:
To find the least number that should be added to 3857 so that the sum is exactly divisible by 5, 6, 4, and 3, we will follow these steps: ### Step 1: Find the LCM of 5, 6, 4, and 3 To find the least common multiple (LCM), we first find the prime factorization of each number: - 5 = 5 - 6 = 2 × 3 - 4 = 2² - 3 = 3 Now, we take the highest power of each prime factor: - The highest power of 2 is 2² (from 4) - The highest power of 3 is 3¹ (from 6 and 3) - The highest power of 5 is 5¹ (from 5) Thus, the LCM is: \[ LCM = 2² × 3¹ × 5¹ = 4 × 3 × 5 = 60 \] ### Step 2: Find the nearest multiple of LCM (60) greater than 3857 Next, we need to find the smallest multiple of 60 that is greater than 3857. We divide 3857 by 60: \[ 3857 ÷ 60 \approx 64.2833 \] The next whole number is 65, so we multiply: \[ 60 × 65 = 3900 \] ### Step 3: Calculate the difference between 3900 and 3857 Now, we find the difference between 3900 and 3857: \[ 3900 - 3857 = 43 \] ### Conclusion The least number that should be added to 3857 to make it divisible by 5, 6, 4, and 3 is **43**. ---
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KIRAN PUBLICATION-LCM AND HCF -Questions Asked In Previous SSC exams (Type -IV)
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  6. The smallest five digit number which is divisible by 12, 18 and 21 is:

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