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If x + y = a and xy = b^(2) then the...

If ` x + y = a and xy = b^(2)` then the value of ` x^(3) - x^(2) y - xy^(2) + y^(3)` in terms of a and b is

A

`( a^(2) + 4 b ^(2)) a `

B

` a^(3) - 3 b ^(2)`

C

` a^(3) - 4 b ^(2) a `

D

` a^(3) + 3 b ^(2)`

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The correct Answer is:
To solve the problem, we need to find the value of \( x^3 - x^2y - xy^2 + y^3 \) in terms of \( a \) and \( b \), given that \( x + y = a \) and \( xy = b^2 \). ### Step-by-Step Solution: 1. **Rewrite the Expression:** We start with the expression: \[ x^3 - x^2y - xy^2 + y^3 \] We can rearrange this expression as follows: \[ x^3 + y^3 - x^2y - xy^2 \] 2. **Use the Sum of Cubes Formula:** The sum of cubes can be expressed using the formula: \[ x^3 + y^3 = (x + y)(x^2 - xy + y^2) \] Since \( x + y = a \), we substitute: \[ x^3 + y^3 = a(x^2 - xy + y^2) \] 3. **Express \( x^2 + y^2 \):** We know that: \[ x^2 + y^2 = (x + y)^2 - 2xy = a^2 - 2b^2 \] Therefore, we can substitute this into our expression for \( x^3 + y^3 \): \[ x^3 + y^3 = a((a^2 - 2b^2) - b^2) = a(a^2 - 3b^2) \] 4. **Combine the Terms:** Now we need to simplify \( -x^2y - xy^2 \): \[ -x^2y - xy^2 = -xy(x + y) = -b^2a \] 5. **Final Expression:** Combining everything, we have: \[ x^3 - x^2y - xy^2 + y^3 = a(a^2 - 3b^2) - b^2a \] Simplifying this gives: \[ = a^3 - 3ab^2 - ab^2 = a^3 - 4ab^2 \] Thus, the final result is: \[ \boxed{a^3 - 4ab^2} \]
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