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The side BC of a right-angled triangle A...

The side BC of a right-angled triangle ABC `(angle ABC = 90^@)` is divided into four equal parts at P, Q and R respectively. If `AP^2+AQ^2+AR^2=3c^2+7na^2`, then n is equal to:

A

`- (3)/(4)`

B

`- (1)/(8)`

C

`(3)/(4)`

D

`(1)/(8)`

Text Solution

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The correct Answer is:
B
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