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The value of a and b in 3 (7)/axxb(3)/15...

The value of a and b in `3 (7)/axxb(3)/15 = 8` is equal to

A

`2,11`

B

`11,2`

C

`1,1`

D

`2,1`

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The correct Answer is:
To solve the equation \( \frac{3 \cdot \frac{7}{a} \cdot \frac{b}{3}}{15} = 8 \), we will follow these steps: ### Step 1: Simplify the Equation Start by simplifying the left-hand side of the equation: \[ \frac{3 \cdot \frac{7}{a} \cdot \frac{b}{3}}{15} = \frac{7b}{15a} \] So, we rewrite the equation as: \[ \frac{7b}{15a} = 8 \] ### Step 2: Cross-Multiply Cross-multiply to eliminate the fraction: \[ 7b = 8 \cdot 15a \] This simplifies to: \[ 7b = 120a \] ### Step 3: Express b in Terms of a Now, we can express \( b \) in terms of \( a \): \[ b = \frac{120a}{7} \] ### Step 4: Find Suitable Values for a and b Since \( a \) and \( b \) must be integers, we need \( 120a \) to be divisible by \( 7 \). We can check the options given (211, 11, 211, or 21) to find suitable values. 1. **Option 1: \( a = 11 \)** \[ b = \frac{120 \cdot 11}{7} = \frac{1320}{7} = 188.57 \quad (\text{not an integer}) \] 2. **Option 2: \( a = 21 \)** \[ b = \frac{120 \cdot 21}{7} = \frac{2520}{7} = 360 \quad (\text{is an integer}) \] ### Step 5: Verify the Solution Now, we can verify if \( a = 21 \) and \( b = 360 \) satisfy the original equation: \[ \frac{3 \cdot \frac{7}{21} \cdot \frac{360}{3}}{15} = \frac{3 \cdot \frac{7}{21} \cdot 120}{15} \] This simplifies to: \[ \frac{3 \cdot \frac{7 \cdot 120}{21 \cdot 15}} = \frac{3 \cdot 7 \cdot 8}{21} = \frac{168}{21} = 8 \] Thus, the values of \( a \) and \( b \) are: \[ a = 21, \quad b = 360 \] ### Final Answer The values of \( a \) and \( b \) are \( 21 \) and \( 360 \) respectively. ---
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