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Calculate the wavelengths of the first l...

Calculate the wavelengths of the first line and the series limit for the Lyman series for hydrogen `(R_(H)=109678 cm^(-1))`.

Text Solution

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For Lyman series, `n_(1)=1`
First line or line of longest wavelength in Lyman series, `n_(1)=1 and n_(2)=2.(1)/(lambda)=R_(H)[(1)/(1^(2))-(1)/(2^(2))] =(3)/(4)R_(H)`
`lambda=(4)/(3) xx (1)/(R_(H)) =(4)/(3xx109678)=1215.7xx10^(-8)cm=1215.7Å`
Series limit or line of shortest wavelength for Lyman series, `n_(1)=1 and n_(2)= prop`.
Therefore, `(1)/(lambda)=R_(H)[(1)/(1^(2))-(1)/(prop^(2))]= R_(H) rArr lambda=(1)/(109678)=9.117xx10^(-6)cm=911.7Å`
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