`4x-5(2x-3)=1-3x`

Sovle x(x+2)^2(x-1)^5 (2x-3)(x-3)^4 ge 0

Solve x(x+2)^2(x-1)^5(2x-3)(x-3)^4geq0.

Solve x(x+2)^2(x-1)^5(2x-3)(x-3)^4geq0.

Simplify: (x^2-3x+2)(5x-2)-\ (3x^2+4x-5)\ (2x-1)

Check whether the following are quadratic equation (i) (x+1)^2=2(x-3) (ii) x^2-2x=(-2)(3-x) (iii) (x-2)(x+1)=(x-1)(x+3) (iv) (x-3)(2x+1)=x(x+5) (v) (2x-1)(x-3)=(x+5)(x-1) (vi) x^2+3x+1=(x-2)^2 (vii) (x+2)^3=2x(x^2-1) (viii) x^3-4x^2 – x + 1 = (x – 2)^3

Simplify the following 4x-(3x+3)-[2x-4[x+3(x-5)}]

Solve for x: 11^(4x-5)*3^(2x)=5^(3-x) * 7^(-x) .

Solve each of the following equations and also check your result in each case: ((45-2x))/(15)-((4x+10))/5=((15-14 x))/9 5((7x+5)/3)-(23)/3=13-(4x-2)/3 (7x-1)/4-1/3\ (2x-(1-x)/2)=(10)/3 (0. 5(x-0. 4))/(0. 42\ )-(0. 6(x-2. 71))/(0. 42)=x+6. 1

The number of irrational roots of the equation (4x)/(x^2+x+3)+(5x)/(x^2-5x+3)=-3/2 is a. 4 b. 0 c. 1 d. 2

The number of irrational roots of the equation (4x)/(x^2+x+3)+(5x)/(x^2-5x+3)=-3/2 is (a) 4 b. 0 c. 1 d. 2