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B2CD,,BCD4,B5CD, BC6D...

`B_2CD,___,BCD_4,B_5CD, BC_6D`

A

`B_2CD`

B

`BCD_2`

C

`BC_3D`

D

`BCD_7`

Text Solution

Verified by Experts

The correct Answer is:
C
`B_2CD to BC_3D to BCD_4 to B_5CD to BC_6D`
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