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If x = cos theta and y = sin^(3) theta, ...

If `x = cos theta and y = sin^(3) theta,` then `|(yd ^(2)y)/(dx ^(2))+((dy)/(dx))^(2)|` at `theta=(pi)/(2)` is:

A

`sin 2theta sec theta`

B

`3 cos 2theta " cosec"theta`

C

`sec^(2)thetasin theta`

D

`3" cosec"^(2) thetacos theta`

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