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A wire of resistance 1 Omega is elongate...

A wire of resistance 1 `Omega` is elongated by 10%. The resistance of the elongated wire is

A

2 R

B

16 R

C

4 R

D

0.5 R

Text Solution

Verified by Experts

The correct Answer is:
B
16 R
Explanation: As I increases to 4l. A decreases to `(A)/(4)`.
`(R.)/(R)=(l.)/(l)xx(A)/(A.)`
`=(4l)/(l)xx(A)/((A)/(4))`
R.=16R`
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