SI unit of permittivity is

Options

A. `Nm ^(2) C ^(-2)`
B. `C ^(2) N ^(-2) m ^(-2)`
C. `CN ^(-1) m ^(-1)`
D. `C ^(2) N ^(-1) m ^(-2)`

Answer

D

Explanation

`C ^(2) N ^(-1) m ^(-2)`
According to Columb.s law
`F = ( q _(1) q _(2))/( 4pi epsi _(0) r ^(2))`
To find `epsi _(0)` equation can be written as:
`epsi _(0) = (q _(1) q _(2))/( 4pi F r ^(2))`
Subsititing all the S.I. units of given quantities of the above equation.
`= (C. C)/( N.m ^(2)) = C ^(2) N ^(-1)m ^(-1).`